Force acting on body of mass 2kg is 0.49N is brought to rest in 6sec. Calculate acceleration of body
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Answer:
Given -
F = 0.49 N
v = 0
m = 2kg
t = 6 sec.
a = ?
First we have to find u
F = m ( v - u )/t
0.49 = 2 ( 0 - u )/6
0.49= -2u /6
0.49×6/2 = -u
u = -1.47 m/s
Now acceleration
v = u + at
0 = -1.47 + a × 6
1.47 = 6 × a
a = 1.47/6
a = 0.245 m/s^2
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