Question

Force acting on body of mass 2kg is 0.49N is brought to rest in 6sec. Calculate acceleration of body​

Answer 1

Answer:

Given -

F = 0.49 N

v = 0

m = 2kg

t = 6 sec.

a = ?

First we have to find u

F = m ( v - u )/t

0.49 = 2 ( 0 - u )/6

0.49= -2u /6

0.49×6/2 = -u

u = -1.47 m/s

Now acceleration

v = u + at

0 = -1.47 + a × 6

1.47 = 6 × a

a = 1.47/6

a = 0.245 m/s^2

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