Question

Force acts for 0.1 s on a body of mass 2.0 kg initially at rest.The force is then withdraw and the body moves with a velocity of 2ms.Find the magnitude of force

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Answer 1

Answer:

F = 40 N

Explanation:

Given, F = ?

t = 0.1 s

m = 2 kg

u = 0

v = 2 m/s

From equations of motion for uniform acceleration,

v = u + at

2 = 0 + a(0.1)

a = 20 m/s²

Force, F = ma

F = 2(20)

F = 40 N

Thank you.

Answer 2

Given :

• Time = 0.1 seconds
• Initial velocity (u) = 0
• Final velocity (v) = 2 m/s
• Mass (m) = 2 kg

To find :

• Force

According to the question,

$\star \boxed{ \sf \red{v = u + at}}$

Now we will put the values according to the formula,

$\sf{ \: :\implies2 = 0 + a \times 0.1} \\ \sf \::\implies{2 = 0.1a} \\ \:: \implies \sf{a = 2 \times \frac{10}{1} } \\ \: : \implies \sf{a=20 \: ms {}^{ - 1} } \orange \bigstar$

So,the acceleration is 20 m/s...

Now we will calculate the force,

$\star \boxed{ \sf \red{F = ma }}$

• Mass given here is 2 kg &
• Acceleration is 20 m/s

→ 2 × 20

→ 40 N

.°. The force is 40 N...