Question

Force and Pressure
1. A cube of side 0.2 m rests on the
floor, as shown. Given that the cube
has a mass of 50 kg, the pressure
exerted by the cube on the floor
is
(Take g - 10 N kg-1)
(a) 25 Nm-2
(c) 1250 Nm-2
(b) 250 Nm-2
(d) 12500 Nm-2​

Answer 1

Answer:

(d) 12500 N m^-2

Explanation:

Here,

• side of the cube, a = 0.2 m
• mass of the cube, m = 50 kg,
• g = 10 N kg^-1

Pressure exerted by the cube,

P = force/area of the cube

= mg/a*a

= 50*10/0.2*0.2

= 12500 N m^-2

Answer 2

Answer:

$\huge\mathit\blue{Question}$

Force and Pressure

1. A cube of side 0.2 m rests on the floor, as shown. Given that the cube has a mass of 50 kg, the pressure exerted by the cube on the floor is

(Take g - 10 N kg-1)

(a) 25 Nm-2

(c) 1250 Nm-2

(b) 250 Nm-2

(d) 12500 NNm-2

Explanation:

$\huge\mathbf\orange{ required \: Answer}$

$we \: know \: ,$

$\large\underline\pink{\sf F \: = \: ma \: .}$

here force applied by the cube on the floor (F) =50×10=500N

now are of the cube in contact with the surface

A=0.2×0.2=0.04m2

Also pressure(P)=F/A

$\large\underline\pink{\sf So \: Given \: here\: - }$

P =500N/0.04m2

$\huge\mathcal\blue{= \: 12500\: pascal . }$

Therefore, option D is the answer.

Hope it's helpful for you .

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