Physics, asked by chandankkbharad2954, 9 months ago

Force b/w two point charges q1,q2 at a distance r is f. At what distance , force b/w them will be f/8

Answers

Answered by ts765147
0

Answer:

2^(3/2)r (2 root 2)r

Explanation:

f = kq1q2/r^2

=>f' = kq1q2/R^2

also, f' = f/8

=>f/8=kq1q2/R^2

=>

(kq1q2/r^2)/8 = kq1q2/R^2

=>kq1q2/r^2*8 = kq1q2/R^2

=>1/r^2*8=1/R^2

=>r^2*8=R^2

=>r * 8^(1/2) = R

=>R= 2^(1/2)r

Similar questions