force between 2 identical short bar magnets whose centres are r metre apart is 4.8 N when their axes are in the same line. if the separation is increased to 2r metre the force b/w them is reduced to ???
Answers
Answered by
3
If the distance between the two magnets become twice i.e from r to 2r than the force will be the half of it i.e from 4.8 meter to 2.4 meter.
And:- 2.4 metre.
And:- 2.4 metre.
Answered by
19
Answer:
0.3 N
Explanation:
In magnetic dipole ,
F α 1/ r⁴ - Force is inversely proportional to radius
Thus, When the separation is made 2r the force is reduced to below :-
the new Force (F) will becomes = 4.8 / 2⁴ = 4.8 / 16 = 0.3 N
Hence the answer is 0.3 N
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