force between two charges seprated by a certain distance in air isF each charge is obtained and the distance between them is also doubled then force will be
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force between 2 charges F
distance in air F
charge obtained F
distance between them is now double
hence the answer will be 2F
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Answer:
Fnet= F/4
Explanation:
according to coulomb's law
Fnet= q1×q2/r^2
so,if distance doubled then net force will be 1/4th of initial force.
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