Question

Force between two identical bar magnets whose centres rmetre apart is 4.8 newton when their axes are in same line is separation is increased to 2r then force between them is reduced to

Answer 1

The force between the bars is reduced to 0.3 N

Explanation:

Force between two magnetic dipole ∝ (1/r4)

∴ (F2/F1) = (r1/r2)4

Given  r1 = r

r2 = 2r  

F1 = 4.8 N

F2 = 4.8 × (r/2r)4 = 4.8 × (1/16)

F2 = 0.3 N

Thus the force between the bars is reduced to 0.3 N

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