Physics, asked by uttu6228, 11 months ago

Force between two identical charges placed at a distance
of r in vacuum is F. Now a slab of dielectric of dielectric
contrant 4 is inserted between these two charges. If the
thickness of the slab is r/2, then the force between the
charges will become
(a) F (b) 3/5 F
(c) 4/9 F (d) F/2

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Answered by Anonymous

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❤️ Answer❤️

c) 4F/9

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