Physics, asked by nauman7, 1 year ago

force between two identical spheres charged with the same charge is f if 50% charge of one sphere is transferred to the other square then the new force will be​

Answers

Answered by bharati27
51

here is your answer.hope it will help you.

Attachments:

vijayvignaraj23: I didn't understand why u wrote (Q/2*3Q/2) in the step 1
vijayvignaraj23: Please tell me
vijayvignaraj23: When u see it
bharati27: 50% of charge means Q/2
bharati27: then, the charge on the other is 3Q/2
bharati27: total 100% charge..
bharati27: hope you got this
Answered by CarliReifsteck
51

Answer:

The new force between the new charges is \dfrac{3}{4}F.

Explanation:

Given that,

The force between two identical charged sphere with the same charge is F.

Charge on first sphereQ_{1} =Q

Charge on first sphere second Q_{2}=Q

The force between two charges is

F = \dfrac{kQ^2}{r^2}....(I)

If 50% charge of one sphere is transferred to other sphere

Charge on first sphereQ_{1} =Q-\dfrac{50 Q}{100}

Q_{1}=\dfrac{Q}{2}

Charge on second sphere Q_{2}=Q+\dfrac{50 Q}{100}

Q_{2}=\dfrac{3Q}{2}

The new force between the new charges is

F'=\dfrac{k Q_{1}Q_{2}}{r^2}

F' = \dfrac{k \times\dfrac{Q}{2}\times\dfrac{3Q}{2}}{r^2}

F' =\dfrac{k 3Q^2}{4r^2}

From equation (I)

F'=\dfrac{3}{4}F

Hence, The new force between the new charges is \dfrac{3}{4}F.

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