Force between two point charges kept at a distance ‘r’ is F. Find the distance between
them, if the force between them reduces to F/3.
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Answer:
Let the changes be q
1
and q
2
When kept
′
d
′
distance apart, they experience columbic force
Given by,
F=k
d
2
q
1
q
2
(k=
4πϵ
0
1
)
When charges get separated by d
′
, force reduces to F/3.
⇒
3
F
=k
d
‘2
q
1
q
2
From above,
3d
2
=d
′2
⇒d
′
=
3
d (Ans)
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