Force between two stationary charges, when placed in free space is 10N. If they are placed in a medium relative permittivity 5, the force between them is (a) 50N (b) 2N (c) 0.5N (d) 10N
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Answer:
answer is 2N
F med = F vacc / E (permitivity of medium)
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Literacy in India is a key for social-economic progress. Despite government programmes, India's literacy rate increased only 77%. The 2011 census, indicated a 2001–2011 literacy growth of 9.2%, which is slower than the growth seen during the previous decade.
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