force between two stationary charges ,when placed on free space is 10 n .If they are placed in a medium of relative permittivity 5 ,the force between them is
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Electric Charges and Fields
Problems Based on Coulomb's Law
The force between two charg...
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Asked on December 27, 2019 by
Boreddy Kolluri
The force between two charges when placed in free space is 5 N.If they are in a medium of relative permittivity 5, the force between them willbe
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Fe in free surface
Fe=
4πε
0
1
r
2
q
2
=5N
In medium
Fe
m
=
4πε
0
ε
r
1
r
2
q
2
Fe
m
=
ε
r
Fe
=
5
5N
=1N
Option A is correct.
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