Force experienced by a wire of length 10 cm kept at an angle of 30 degree to the uniform
magnetic field of 0.5 Tesla and carrying a current of 6A is
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Answer:
F
ˉ
=i(
l
×
B
)
F=BilSinθ
=0⋅02×5×0⋅1×sin30
0
=5×10
−3
N
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