Question

force experienced by charge 'q' moving with velocity 'v' Force experienced by charge ‘q ’ moving with velocity ‘v’ in a magnetic field ‘B’ is given by F = q v B. Find

the dimensions of magnetic field​

Answer 1

$f = q \: v \: b \: \\ b \: = \frac{f \: }{q \: v \: } \\ b \: = \frac{ {m \: l \: t \: }^{ - 2} }{a \: t \: l \: {t \: }^{ - 1 \: } } \\ \\ b \: = \frac{m \: l \: {t \: }^{ - 2} }{ \: a \: l \:}$

#Bebrainly

#Rajput

✌️❤️❤️❤️❤️❤️✌️

Answer 2

Answer:

the dimensions is ML(T-2)/A

Explanation:

newton = coulomb X m/s X B

B = (Newton X second )/ coulomb

= ML(T-2)*T/AT

=ML(T-2)/A