Force, F = 30 kg - wt = 30 x 10 = 300N
Angle between force and ground, 0 = 60°
The work done by the gardener,
W = F s = Fs cos 0 = 300 x 30 x cos 60°
W = 4500 J
EXAMPLE 2 A Coolie
A coolie is holding a bag by applying a force of 15 N
He moves forward and covers the horizontal distance of a
m and then he climbs up and covers the vertical distance
of 10 m. What will be the work done by him?
The net work done by coolie is the sum of work done to
cover the horizontal direction and the work done to climb
up in the vertical direction.
Sol Given
F = 15 N, S, = 8 m and s, = 10 m
Answers
Answer:.
Work equals the force F times the displacement s times the cosine of the angle F,s between the force F and the displacement s:
W = (Fs cos F,s)
If we rewrite work as W = (F cos F,s)s,
we see from Fig. 1b that we may say, alternatively, that work is the component of the force, F cos F,s, in the direction of the displacement times the displacement.
From Fig. 1c we find we may also write
W = F (s cos F,s) or work is the product of the force and the component of the displacement, (s cos F,s), in the direction of the force.
Explanation: MARK ME BRAINILIST
Work equals the force F times the displacement s times the cosine of the angle F,s between the force F and the displacement s:
W = (Fs cos F,s)
If we rewrite work as W = (F cos F,s)s,
we see from Fig. 1b that we may say, alternatively, that work is the component of the force, F cos F,s, in the direction of the displacement times the displacement.
From Fig. 1c we find we may also write
W = F (s cos F,s) or work is the product of the force and the component of the displacement, (s cos F,s), in the direction of the force.
Explanation: