Force F = (42 - 2x) i N starts acting on a particle of mass 3 kg initially at rest at origin.
What is its speed after moving 6m?
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Answer:
Explanation:
FORCE=42-2X
MASS =3 KG
INITIAL VELOCITY= 0
DISTANCE MOVED= 6M
FORCE APPLIED ON MOVING 6 M=42-2-6
=42-12
=30 N
WE KNOW,
F=MA
30=3A
A=10M/S^2
WE KNOW THAT,
V²-U²=2AS
V=?
V²-0=2*10*6
V²=120
V=10.9 M/S.
HOPE IT HELPS.
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