Physics, asked by sakshamjaiswal2922, 8 months ago


Force F = (42 - 2x) i N starts acting on a particle of mass 3 kg initially at rest at origin.
What is its speed after moving 6m?

Answers

Answered by raj3294
0

Answer:

Explanation:

FORCE=42-2X

MASS =3 KG

INITIAL VELOCITY= 0

DISTANCE MOVED= 6M

FORCE APPLIED ON MOVING 6 M=42-2-6

                                                         =42-12

                                                         =30 N

WE KNOW,

F=MA

30=3A

A=10M/S^2

WE KNOW THAT,

V²-U²=2AS

V=?

V²-0=2*10*6

V²=120

V=10.9 M/S.

HOPE IT HELPS.

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