Force f bar =4i cap -10j cap is applied from a distance of r bar=-5i cap -4j cap to a disc from its axis of rotation. Find the torque applied (T = f bar cross r bar)
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Answer:
of=4i^-10j^
or=-5i^-4j^
T=f(r)
T=fo-or
T=4i^-10j^+5i^+10j^
T=i^ ans.
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