Force f is applied on a body making an angle 30 degrees on a horizontal and the force along the y-direction is 200 . find the horizontal component and the net force.
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Answer:
fx=200√3N
Explanation:
Components of f are
fy=fsin30°
fx=fcos30°
Since fy=200N
fsin30°=200
f/2=200
f=400N
therfore horizontal component is
fcos30°=fx
fx=400*√3/2
fx=200√3N
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