Force F on a particle moving in a straight line
varies with distance d as shown in the figure. The
work done on the particle during its displacement
of 12 m is
[AIPMT (Prelims)-2011]
1 F (N)
7
0 3
(1) 135
(3) 21 J
- d(m)
12
(2) 18 J
(4) 26 J
Answers
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Answer:
where is the figure.........
Explanation:
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Answered by
0
Answer:
The work done by the particle during its displacement of 12 m is 13 J.
Explanation:
Given: Force = F
displacement = d (values as shown in attached file)
To find: The work done during the given displacement.
Solution: #For work done, we know that:
W = Area of force-displacement graph
So, we find the area of force-displacement graph for the numerical values of work done.
Area = area of rectangle + area of triangle
[Refer to the attached image]
Area = 4 × 2 + 1/2 × 2 × 5
Area = 8 + 5
Area = 13 J = Work done
Hence, the work done by the particle during its displacement of 12 m is 13 J.
Attachments:
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