Physics, asked by greeshmarose2954, 4 days ago

force in medium (k) F= 1/4pi epsilon0 q1q2/(root k×r)^2. how that root k?​

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Answered by Reetdhillon0720
1

Answer:

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Explanation:

Coulomb’s law:  E(r)=14πε0qr2   =   kqr2 , where  ε0  is the Vacuum permittivity.

There is an old interpretation of it but don't take it too seriously, because it's not entirely correct. So, here it goes: the electric field strength  E(r)  of an electric charge  q  at a distant  r  is given by (just rewrite it as)  E(r)=(q/ε0)/A(r) , where  A(r)=4πr2  is the surface area of the sphere of radius  r  centered at the location of the electric charge  q . Now, when you rewrite it like this, the electric field strength  E(r)  can be interpreted as the local density of electric field lines (i.e. electric flux) at that point, that is total number of lines per unit area  ∼(q/ε0)/A(r) . (This is the reason why in old texts electric field strength is also refereed as electric filed density.)

So in that sense  q/ε0  is basically the total number of electric field lines (or, electric flux) emerging from a point electric charge  q . Clearly, this number is finite and we know that electric field lines is not a physical concept but rather a geometric construct invented to explain the relative strengths of electric charges and their electric field strengths. Therefore, it must be taken with a pinch of salt.

Thus, according to this interpretation, one can say that  1/ε0  is the total number of electric field lines (or, electric flux) emanating from a unit electric charge. Also, note that it’s the inverse of the vacuum permittivity.

Answered by vvsgs0512
1

Explanation:

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