Question

force is applied for a bullet fet 0.02 second and it acavired velocity of 150 metre second calculate the force applied by gun if man of the bullet is 200 gram​

Answer 1

We are given that

u = 18 km h¹ = 5 ms ¹

v = 36 km h¹ = 10 m s' and

t = 5 s.

(v-u) t a=

(i) From Eq. (8.5) we have 10 ms. - 5 ms¹ 5s = 1 ms ²

Answer 2

Answer:

The force applied on the bullet is 1500 N

Explanation:

Given that,

  Velocity acquired by the bullet, v = 150 m/s

  Mass of the bullet , m = 200 g  = 0.2 kg

  Time, t = 0.02 seconds

We know that,

                  F = p / t

                 where,

                         F  →  Force

                         p  →   Momentum

                         t   →  time

 Force, F = p / t = (m $\times$ v ) / t = (0.2 $\times$ 150) / 0.02 = 1500N