Force of 100 N acts on body of mass 20 kg for 10 s . If the body is initially at rest and all the directions involved are same straight line , find , (i) Displacement of the body (ii) final velocity of the body (iii) energy transferred to the body by applied force.
Answers
Answer:
Q1. A force of 7N as on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. Wtm is the work done in this case?
Ans. F=7N
s = 8 m
W = F × s
= 7 N × 8 m
W = 56J
∴ Work done is 56 J.
NCERT TEXTBOOK PAGE 149
Q1. When do we say that work is done?
Ans. Work is said to be done when force applied on an object shows the displacement in that object.
W = F x s.
Q2. Write an expression for the work done when a force is acting on an object in the direction of its displacement.
Ans. Work done = W
Force = F
Displacement = s
Work done is equal to the product of the force and displacement.
W = F × s
Q3. Define 1 J of work.
Ans. 1 Joule of work is said to be done when force of 1 Newton acts on a by and shows displacement of 1 metre.
Q4. A pair of bullocks exerts a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughing the length of the field?
Ans. Force = 140 N
s = 15m
W = ?
W = F × s
= 140 N x 15 m
= 2100 Nm
W = 2100 J
∴ Work done in ploughing the length of the field is 2100 J.
Explanation:
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