force of 1200n acts on the surface of area 10cm normally. what is the pressure on the surface
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Hey there!
Given,
Force(F) = 1200 N
Area (A) = 10 cm² = 0.001 m²
We know,
Thrust is the force acting normally to a surface.
So, Thrust = 1200 N
And, Pressure = Thrust / Area
= 1200 / 0.001
= 1200000 Pa
= 1.2 × 10⁶ Pa
Hope it Helps You!
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