Physics, asked by shalinisrini2009, 1 month ago

force of 15 n causes and displacement of 5 metre in its own direction what is the magnitude of work done and it's SI unit​

Answers

Answered by Anonymous
36

AnswEr :

  • The magnitude of work done is 75 Joules.

Explanation :

We are given with the force as well as displacement values in its own direction, that is,

  • Force, F = 15 N.
  • Displacement, s = 5 m.

We have to find out the magnitude of work done.

Given that the force of 15 N causes and displacement of 5 metre in its own direction so the cosθ value will be .

We know that, if we are given with force and displacement values in its own direction, we have the required formula, which says,

→ W.D = Fs cos(θ)

Where we have the values as :

  • W.D = unknown.
  • F = 15 N.
  • s = 5 m.

By using the formula and substituting the given values in the formula, we get :

→ W.D = 15 × 5 × cos(0)

→ W.D = 75 × cos(0)

→ W.D = 75 × 1

→ W.D = 75

Hence, the magnitude of work done is 75 Joules.

Additional information :

Learn about work done :

  • Work done is the product of force and displacement.
  • Work done is represented as W.D.
  • The SI unit of work done is Joules (J).
  • The other units of work done is Foot-pound, Erg.
  • The derivations from other quantities are W = Fs and W = τθ.
Answered by Itzheartcracer
30

Given :-

Force of 15 n causes and displacement of 5 metre in its own direction

To Find :-

Work done

Solution :-

We know that

W = Fs

Where,

W = Work done

F = Force applied

s = Displacement

By putting the values

W = 15 × 5

W = 75 J

Hence

Work done is 75 Joule

SI unit of work done is Joule(J)

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