force of 4 N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at
rest, find its velocity when force stops acting on it.
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Explanation:
A force of 4N acts on a body of mass 2kg for 4 seconds.
mass of body, m = 2kg
initial velocity of body , u = 0 m/s
force acts on the body , F = 4N
from Newton's 2nd law,
F = ma
4 = 2a => a = 2m/s²
force acting on body for 4sec.
so, velocity of body changes in 4 sec.
use formula, v = u + at
v = 0 + 2 × 4 = 8 m/s
hence, body moves with velocity 8m/s . now, applied force is removed after 4sec then, body moves with constant velocity. hence, acceleration = 0
we have to find distance covered in 10 sec after force starts acting on it.
so, total distance = distance covered in first 4 sec + distance covered in rest 6 sec
= {0 × 4 + 1/2 × 2 × 4²} + {8 × 6 + 1/2 × 0 × 6²}
= 16 + 48 = 64m
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