Science, asked by sanaprnt, 7 months ago

force of 4 N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at

rest, find its velocity when force stops acting on it. ​

Answers

Answered by Abidkhanatnoone
1

Answer:

Explanation:

A force of 4N acts on a body of mass 2kg for 4 seconds.

mass of body, m = 2kg

initial velocity of body , u = 0 m/s

force acts on the body , F = 4N

from Newton's 2nd law,

F = ma

4 = 2a => a = 2m/s²

force acting on body for 4sec.

so, velocity of body changes in 4 sec.

use formula, v = u + at

v = 0 + 2 × 4 = 8 m/s

hence, body moves with velocity 8m/s . now, applied force is removed after 4sec then, body moves with constant velocity. hence, acceleration = 0

we have to find distance covered in 10 sec after force starts acting on it.

so, total distance = distance covered in first 4 sec + distance covered in rest 6 sec

= {0 × 4 + 1/2 × 2 × 4²} + {8 × 6 + 1/2 × 0 × 6²}

= 16 + 48 = 64m

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