Question

Force of 800 newton is applied on a mass of 0.16 tons . If the mass initially at rest and travels for 10 seconds on application of force , find the distance covered by the mass.​

Answer 1

Answer:

distance=250 m

Explanation:

0.16 tons=160kgs

F=Mass x acceleration

800=160 X a

a=800/160

a=5m/s^2

S =ut+1/2at^2

S=0+1/2(5) (10x10)

S=250 m

Answer 2

Explanation:

given, F = 800N

ma = 800.

0.16 ×1000 × a = 800

hence, a = 5 m/ s^2

now , u = 0 m/s

t = 10 seconds

a = 5 m/s^2

by second equation of motion

s = ut + 1/2at^2

0 × 20 + 1/2 × 5 × 10× 10

hence , distance covered = 250 metre