Force of attraction b/w two point charges placed at a distance d is F. What distance apart should they be kept in the same medium so that force b/w them is F/3 ? Explain clearly plz and fast.
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Answered by
240
Let us consider two point charges q1 and q2, placed at a distance d.
Force of attraction,
F = k (q1q2)/d²________(1)
Now, if the force becomes F/3, then let the distance between the point charges be r
Now, force of attraction,
F' = F/3 = k (q1q2)/r²______(2)
dividing equation, (1) and (2),we get
3 = r²/d²
⇒r² = 3 d²
⇒r = d√3
If the distance between them is d√3, the force will be F/3.
Force of attraction,
F = k (q1q2)/d²________(1)
Now, if the force becomes F/3, then let the distance between the point charges be r
Now, force of attraction,
F' = F/3 = k (q1q2)/r²______(2)
dividing equation, (1) and (2),we get
3 = r²/d²
⇒r² = 3 d²
⇒r = d√3
If the distance between them is d√3, the force will be F/3.
Answered by
52
Consider two point charges q1,q2
At a distance D
Force between them is F = kq1q2/d^2
Let the distance between the two charges be r when the force between them is F/3
F/3 = kq1q2/r^2
Dividing equation 2 by equation by 1
1/3 = d^2/r^2
r^2 = 3(d^2)
r = √3 D
There fore when the distance between the two point charges is √3d the force becomes F/3
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