Question

Force of attraction between two bodies at a certain separation is 10 N. What will be the force of attraction when the distance of separation is doubled?​

Answer 1

Answer:

Given, the force of attraction between the two bodies is 10N. ... So, the force of attraction between the two bodies when the separation between them is reduced to half will be 40N.

Explanation:

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Answer 2

Explanation:

Given, the force of attraction between the two bodies is 10N.

So, we can write that,

F=GmMr2=10N

Now, the separation between the two bodies are reduced to half of the initial separation. So, the final separation between the two bodies will be r2 .

Now, the force of attraction between the two bodies will be,

Ff=GmM(r2)2=4GmMr2

Putting the value from the initial condition on the above equation,

Ff=4×10N=40N

So, the force of attraction between the two bodies when the separation between them is reduced to half will be 40N.