Force of attraction between two charges at a distance 'd' is found to be 'F'.What will be the new distance of separation if the force becomes twice of 'F'?
Answers
Hey dude your answer is
The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.
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Answer:
Let us consider two point charges q1 and q2, placed at a distance d.
Force of attraction,
F = k (q1q2)/d²________(1)
Now, if the force becomes F/3, then let the distance between the point charges be r
Now, force of attraction,
F' = F/3 = k (q1q2)/r²______(2)
dividing equation, (1) and (2),we get
3 = r²/d²
⇒r² = 3 d²
⇒r = d√3
If the distance between them is d√3, the force will be F/3.
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