Question

Force on an electric dipole of dipole moment 2Cm placed in a uniform electric field of magnitude 10V/m Has maximum value 20N Has minimum value 10N Both (1) and (2)​

Answer 1

Given:

Electric dipole of dipole moment 2Cm placed in a uniform electric field of magnitude 10V/m.

To find:

Max and Min Force on dipole?

Calculation:

When dipole is placed perpendicular to the field intensity, both the charges of the dipole experience equal and opposite force.

Irrespective of the orientation of dipole w.r.t the electric field, the net force will always be zero.

$F_{ + } = qE \: and \: F_{ - } = - qE$

Hence, net force :

$F_{ net} = qE - qE$

$\implies F_{ net} = 0$

So, net force is always ZERO.

Answer 2

Explanation:

Given:

Electric dipole of dipole moment 2Cm placed in a uniform electric field of magnitude 10V/m.

To find:

Max and Min Force on dipole?

Calculation:

When dipole is placed perpendicular to the field intensity, both the charges of the dipole experience equal and opposite force.

Irrespective of the orientation of dipole w.r.t the electric field, the net force will always be zero.

F_{ + } = qE \: and \: F_{ - } = - qEF

+

=qEandF

−

=−qE

Hence, net force :

F_{ net} = qE - qEF

net

=qE−qE

\implies F_{ net} = 0⟹F

net

=0

So, net force is always ZERO.