Question

force on proton in an electric field of 1.6V/m​

Answer 1

Force on charge particle moving under a electric field is

F=q×E

where q is the value of charge and E is the electric field.

here q=1.6 ×10^-19 C

E=1.6 V/m

so force F= {1.6 ×10^-10}×1.6

=2.56×10^-19 N