Question

force required in accelerating a 3kg mass at 5m/s^2 and 4kg mass at 4m/s^2 will be
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Answer 1

f= ma

f = 3 × 5

= 15 N

f= 4 × 4

= 16 N

Answer 2

The force exerted by the first and second body respectively is 15 N and 16 N.

• Force has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Here, according to the given information, we are given that,

The mass of the first body at 5 $m/s^2$  is equal to 3 kg.

Acceleration of this body is equal to 5 $m/s^2$.

The mass of the body at 4 $m/s^2$ is equal to 4 kg.

Acceleration of the this body is equal to 4 $m/s^2$.

Now, we know that,

Force = Mass × Acceleration.

Then, the force exerted by the first body = $3.(5) = 15 N.$

The force exerted by the second body = $4.(4) = 16 N.$

Hence, the force exerted by the bodies having 3 kg mass at 5 $m/s^2$ and 4 kg mass at 4 $m/s^2$ respectively is 15 N and 16 N.

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