Question

force required to separate two glass plates having surface area of 10^-3 m-2 with a film of water 0.05 mm between them is where the surface tension of water is 70*10^-3 N/m plz give explaination of this​

Answer 1

Answer:

The force required to separate two glass plates = 2.8 N

Step-by-step explanation:

Given:

• Surface area of each glass plate = 10⁻³ m²
• Thickness of film of water = 0.05 mm = 0.05 × 10⁻3 m
• Surface tension of water = 70 × 10⁻³ N/m

To find:

• The force required to separate two glass plates.

Solution:

First we will find the length of glass plate by using formula and then substituting the value in the formula to calculate the force, we can easily find out the force required to separate two glass plates.

Let's find out...

• Length = ( 2 × Area )/Thickness
• Length = (2 × 10⁻3)/( 0.05 × 10⁻3)
• Length = (2 × 10⁻3 × 1000 × 100 )/5
• Length = (2 × 1000 × 100 )/5 × 1000
• Length = (2 × 100 )/5
• Length = 2 × 20
• Length = 40 m

• Force = Surface tension × length
• Force = 70 × 10⁻³ × 40
• Force = (70 × 40)/1000
• Force = 2800/1000
• Force = 28/10
• Force = 2.8 N

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