Force was applied over a mass of 40 kg by which its velocity becomes 5 M per second from 2 m per second find the magnitude of work done by force applied
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According to the work-energy conversion theorem;
Work done by the force = Change in Kinetic energy
Work done by the force = (1/2)*m*(v2 - u2)
Work done = 0.5*20*(4–25) = -210 J
Since work done by the force is opposite to the direction of velocity, the work done by the force is negative!
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Work done by the force = Change in Kinetic energy
Work done by the force = (1/2)*m*(v2 - u2)
Work done = 0.5*20*(4–25) = -210 J
Since work done by the force is opposite to the direction of velocity, the work done by the force is negative!
Plz do mark as brainliest
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