Question

force year ago a father was 6 times as old as his son 10 years later the father will Bitto and half times at old as his son will be determined their percent age​

Answer 1

Answer:

The son's age is 4% of his father's age. Son is 10 years old and father is 40 years old.

Explanation:

Let age of father be x and that of son be y.

According to the question,

x-4=6(y-4)

x-4=6y-24

x=6y-20 - - - eqn.1

Also

x+10=5/2(y+10)

x+10=5y+50/2

2x+20=5y+50 - - eqn.2

Substituting value of eqn.1 in eqn.2

2(6y-20)+20=5y+50

12y-40+20=5y+50

12y-5y=50+40-20

7y=70

y=10

Therefore x is equal to 40. We can get this by Substituting value of y in eqn. 1

Thus,

10 ×40 /100=4%