Question

Forceon a moving charge in uniform magnetic field and electric field derivation

Answer 1

In the first frame S in which the magnet is at rest, the electron feels E=0 and B not null. In S’ moving with v, in which the electron is at rest and the magnet travels with –v, the electron feels E’=gammavxB=vxB’ and B’=gammaB, according to the Lorentz transformation. The forces are F=qvxB and F’=qE’=qgammavxB, obviously different while the lineal momentum Fdt=F’dt’ is conserved of course. But the problem is to understand the physics origin of the electric field E’


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