Question

forces 3N , 4N , and 12N act at a point in mutually perpendicular directions . the magnitude of resultant force in newton is ....

Answer 1

The magnitude of resultant forces are determined by;
F = √F1² + F2² + F3²
F = √3² + 4² + 12²
F = √9 + 16 + 144
F = 13 N

Answer 2

F in Newton is 13 N

Given:

The three force given are 3 N, 4 N, and 12 N.  

Solution:

They all act at a point which is mutually perpendicular to each other.

Thereby, we need to calculate the magnitude of resultant force of two force

$Resultant =\sqrt{3^{2}+4^{2}}$

$=\sqrt{9+16}$

$\therefore \text { Resultant }=5 N$

Now, we can calculate, resultant force and another force,

$Resultant =\sqrt{5^{2}+12^{2}}$

$=\sqrt{25+144}$

$\therefore \text {Resultant}=13 N$