Forces acting on a particle have magnitudes 5N,3N and 1N act in the direction of vectors 6i+2j+3k,3i-2j+6k and 2i-3j-6k respectively.If the particle displaces from a point A(3,-1,-3) to (5,-1,-1),then the work done is
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Answer:
Find the energy received by the surface during time span of 1 minute.
Solution:
the intensity of the light incident is
E
I------
At
Here, I =20 W/cm2, Area A =20
:• 20 =____E_____
20×60
=> E = 20 × 20 × 60
E = 24 × 10 3 J
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