Forces from sides of square acting at point what's the resultant
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R = V radical 3 [R is the BASE of the isosceles triangle formed by the two force-vectors and half the base is R/2 = [V radical 3] / 2 ; and the bisector of the vertical angle is the perpendicular bisector of the base.
Let k be the vertical angle of the isosceles triangle.
Sine (k/2) = [R / 2] / R → {[V radical 3] / 2} / V → radical 3 /2
k/2 = 60 → k = 120
The angles between the two forces is: 180 - 120 = 60 degrees.
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