Forces of 30N, 40N, and 50N act along the sides
AB, BC and CA of an equilateral triangle ABC. The
triangle is of mass 0.5 kg and kept in a vertical
plane as shown in figure, with the side AB vertical.
The net vertical force acting on the triangle will be.
(g = 10 m/s)
(A) 125 N upward
(B)5 N downwards
(C) 15 N upwards
(D) 10 N downwards
Answers
Answered by
7
Answer:
I don't know your answer i am very very sorry
Answered by
0
Answer:
I think there is some error in options. Because as per my calculations the correct answer should be 10N upwards. (P/s - I might be wrong too!)
Explanation:
Using the concept of resolution of Vectors we will get a force of 30 + 5 N in downward direction and force of 45N in upward direction l. Hence, net external force is 10N in upward direction.
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