Question

Forces of 3N, 5N and 7N acting on a particle are in equilibrium, find the angle between the forces 3N and 7N.

Answer 1

Answer:

Using the cosine law,

R² = a² + b² + 2(a.b)

Where a and b are forces and R is their resultant,

(7*7) = (3*3) + (5*5) +2 (3*5) cosθ

49 = 9 + 25 + 30 cosθ

cosθ = 15/30 = 1/2

Thus, θ = 60°

Explanation:

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Answer 2

Answer:

Explanation: various ways are there I have done using law of cosine some can do in other way