Question

Forces of 5√2N and 6√2N are acting on a body of mass 1000 kg at an angle of 60 to each other. Find acceleration, distance covered, and the velocity of mass after 10sec

Answer 1

resultant force=( 6√2)² +(5√2)²+2*6√2*5√2*cos60=182N
F=M×A
A=F/M
A=182÷1000
=0.182m/s²

now,
V=U+A×T
V=0+0.182×10
V=1.82m/s

V=DISPLACEMENT/TIME
D=V×T
D=1.82×10
D=18.2m

Answer 2

Explanation:

hope this will help you