Question

Forces p,2p,3p act along the sides of a triangle formed by the lines x=0,y=0 and 3x+4y=5.Find the magnitude of the resultant and equation of the line of action .​

Answer 1

Answer:

The resultant of 4 vectors in X, Y direction are:

resultant in X direction is

3

P

−

P

=2

P

(in -ve x direction)

In y direction is

4

P

−2

P

=2

P

(in +ve y direction)

So, the net resultant force vector is

R

→

=2

P

→

+2

P

→

angle between both vectors is 90

So magnitude of resultant is 2

2

P in direction of 45

0

from positive y axis in IV quadrant.

solution

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