Question

Ford quadratic EQ 3 x square plus root 8 x-16 find the value​

Answer 1

Answer:

this is the factorisation by middle term spliting and if u want value of x then equate each of the equation by 0

like this:-(x+4)=0 , X=4

(3X-4)=0, X=4/3

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Answer 2

Step-by-step explanation:

${3x }^{2} + \sqrt{8} x - 16 = 0$

we can write

$\sqrt{8} = 2 \sqrt{2}$

Therefore,

$6 \sqrt{2}x - 4 \sqrt{2 }x = 2 \sqrt{2} x$

and

$6 \sqrt{2}x \times - 4 \sqrt{2}x = 48x$

Therefore

$3 {x}^{2} + 6 \sqrt{2}x - 4 \sqrt{2}x - 16 = 0$

$3x( x + 2 \sqrt{2} ) - 4 \sqrt{2} (x + 2 \sqrt{2}) - 16 = 0$

$(3 x - 4\sqrt{2}) + (x + 2 \sqrt{2} )$

Therefore,

the roots are

$x = \frac{4 \sqrt{2} }{3} and \: x = - 2 \sqrt{2}$

I hope this will help you