Question

Form 5 problems each similar to question 1, 2 and 3 and solve.
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Answer 1

Answer:

The problems are:

a) $2^{-1} =\frac{1}{2}$

b) $4^{-1} =\frac{1}{4}$

c) $(\frac{3}{2} )^{-1} =\frac{2}{3}$

d) $(\frac{10}{9} )^{-1} =\frac{9}{10}$

e) $(\frac{3}{8} )^{-1} =\frac{8}{3}$

Question 2 and 3 is based on division.

a) $\frac{1}{2}by2=\frac{1}{2}*\frac{1}{2}=\frac{1}{4}$

b) $\frac{3}{2}by2=\frac{3}{2}*\frac{1}{2}=\frac{3}{4}$

c) $\frac{11}{6}by2=\frac{11}{2}*\frac{1}{2}=\frac{11}{4}$

d) $\frac{4}{9}by3=\frac{4}{9}*\frac{1}{3}=\frac{4}{27}$

e) $\frac{2}{21}by5=\frac{2}{21}*\frac{1}{5}=\frac{2}{105}$

Step-by-step explanation:

Question 1 is based on finding reciprocal.

The problems are:

a) $2^{-1} =\frac{1}{2}$

b) $4^{-1} =\frac{1}{4}$

c) $(\frac{3}{2} )^{-1} =\frac{2}{3}$

d) $(\frac{10}{9} )^{-1} =\frac{9}{10}$

e) $(\frac{3}{8} )^{-1} =\frac{8}{3}$

Question 2 and 3 is based on division.

a) $\frac{1}{2}by2=\frac{1}{2}*\frac{1}{2}=\frac{1}{4}$

b) $\frac{3}{2}by2=\frac{3}{2}*\frac{1}{2}=\frac{3}{4}$

c) $\frac{11}{6}by2=\frac{11}{2}*\frac{1}{2}=\frac{11}{4}$

d) $\frac{4}{9}by3=\frac{4}{9}*\frac{1}{3}=\frac{4}{27}$

e) $\frac{2}{21}by5=\frac{2}{21}*\frac{1}{5}=\frac{2}{105}$

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Answer 2

Answer:

The problems are:

a) $2^{-1}=\frac{1}{2}$

b) $4^{-1}=\frac{1}{4}$

C) $\left(\frac{3}{2}\right)^{-1}=\frac{2}{3}$

d) $\left(\frac{10}{9}\right)^{-1}=\frac{9}{10}$

e)$\left(\frac{3}{8}\right)^{-1}=\frac{8}{3}$

Question 2 and 3 is based on division.

a)$\frac{1}{2} b y 2=\frac{1}{2} * \frac{1}{2}=\frac{1}{4}$

b) $\frac{3}{2} b y 2=\frac{3}{2} * \frac{1}{2}=\frac{3}{4}$

C)$\frac{11}{6} b y 2=\frac{11}{2} * \frac{1}{2}=\frac{11}{4}$

d)$\frac{4}{9} b y 3=\frac{4}{9} * \frac{1}{3}=\frac{4}{27}$

e) $\frac{2}{21} b y 5=\frac{2}{21} * \frac{1}{5}=\frac{2}{105}$

Step-by-step explanation:

Question 1 is based on finding reciprocal.

The problems are:

a) $2^{-1}=\frac{1}{2}$

b)$4^{-1}=\frac{1}{4}$

C) $\left(\frac{3}{2}\right)^{-1}=\frac{2}{3}$

d) $\left(\frac{10}{9}\right)^{-1}=\frac{9}{10}$

e) $\left(\frac{3}{8}\right)^{-1}=\frac{8}{3}$

Question 2 and 3 is based on division.

a) $\frac{1}{2} b y 2=\frac{1}{2} * \frac{1}{2}=\frac{1}{4}$

b) $\frac{3}{2} b y 2=\frac{3}{2} * \frac{1}{2}=\frac{3}{4}$

C) $\frac{11}{6} b y 2=\frac{11}{2} * \frac{1}{2}=\frac{11}{4}$

d)$\frac{4}{9} b y 3=\frac{4}{9} * \frac{1}{3}=\frac{4}{27}$

e) $\frac{2}{21} b y 5=\frac{2}{21} * \frac{1}{5}=\frac{2}{105}$

Form 5 problems each similar to question 1, 2 and 3 and solve.​

https://brainly.in/question/21275266

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