form a ap with first term in 5 and the common diffrence in 3
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Hey mate thank for the question
hope it helps
a=5
d=3
a1=a=5
a2=a+d
a2=5+3=8
a3=a+2d
a3=5+2*3=5+6=11
a4=a+3d=5+3*3=5+9=14
So AP =5,8,11,14
hope it helps
a=5
d=3
a1=a=5
a2=a+d
a2=5+3=8
a3=a+2d
a3=5+2*3=5+6=11
a4=a+3d=5+3*3=5+9=14
So AP =5,8,11,14
Thushi:
thank u bro
bro i have another question write the next three terms the following 1'-1;-3-5........
pls send me in comment itself
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