Form a biquadratic polynomial whose zeroes are 2,4,6,8
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Answer is 2x4 -5x3-10x2+5X -3 hope it helps u bhai
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Hi ,
2, 4 , 6 , 8 are the zeroes of the polynomial
p(x )
Then , ( x -2 ) , ( x - 4 ) , ( x - 6 ) , ( x - 8 ) are
the factors of the p( x ) .
p( x ) = ( x - 2 )( x - 4 ) ( x - 6 ) ( x - 8 )
= (x² - 4x - 2x + 4 ) ( x² - 8x - 6x + 48 )
= ( x² -6x + 4 ) ( x² - 14x + 48 )
= ( x⁴ - 14x³ + 48x² - 6x³ + 84x²- 288x + 4x² - 56x + 192 )
= x⁴ - 20x³ + 136x² - 344x + 192
I hope this helps you.
:)
2, 4 , 6 , 8 are the zeroes of the polynomial
p(x )
Then , ( x -2 ) , ( x - 4 ) , ( x - 6 ) , ( x - 8 ) are
the factors of the p( x ) .
p( x ) = ( x - 2 )( x - 4 ) ( x - 6 ) ( x - 8 )
= (x² - 4x - 2x + 4 ) ( x² - 8x - 6x + 48 )
= ( x² -6x + 4 ) ( x² - 14x + 48 )
= ( x⁴ - 14x³ + 48x² - 6x³ + 84x²- 288x + 4x² - 56x + 192 )
= x⁴ - 20x³ + 136x² - 344x + 192
I hope this helps you.
:)
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