Form a circular sheet of a radius 5cm , a circle of radius 3cm is removed . Find the area of the remaining sheet.
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Area of remaining sheet =
=Area of circle with radius 5cm - Area of circle with radius 3cm
= π5² - π3²
=π[5² - 3²]
=π[25 - 9]
=3.14 × 16
=50.24cm²
Answered by
1
Concept used:-
First find the area with the initial radius, then find the area with the removed radius and subtract it from the initial radius's area.
Radius of circular sheet=5 cm
So, its area=πr²
=22/7×5²
=22/7×25
=550/7 cm²
Now, it is given that a circle of radius of 3 cm is removed.
So, the radius now=3 cm
So, its area=πr²
=22/7×3²
=22/7×9
=198/7 cm²
So, area of the remaining sheet=550/7 cm²-198/7 cm²
=352/7 cm²
=50.285 cm²
First find the area with the initial radius, then find the area with the removed radius and subtract it from the initial radius's area.
Radius of circular sheet=5 cm
So, its area=πr²
=22/7×5²
=22/7×25
=550/7 cm²
Now, it is given that a circle of radius of 3 cm is removed.
So, the radius now=3 cm
So, its area=πr²
=22/7×3²
=22/7×9
=198/7 cm²
So, area of the remaining sheet=550/7 cm²-198/7 cm²
=352/7 cm²
=50.285 cm²
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