Question

form a cubic polynomial who's zeroes are 3 , -1 , and 4​

Answer 1

$let \: the \: zereos \: be \: \alpha , \beta ,\gamma \: \: are \: 3 , - 1 , 4 \: respectively$

${x}^{3} - ( \alpha + \beta + \gamma ) {x}^{2} + ( \alpha \beta + \beta \gamma + \alpha \gamma )x + \\ \alpha \times \beta \times \gamma \\ \\ {x}^{3} - (3 + ( - 1) + 4) {x}^{2} + ((3 \times - 1) + ( - 1 \times 4) + \\ (4 \times 3))x + (3 \times - 1 \times 4) \\ \\ {x}^{3} - 6 {x}^{2} + ( - 3 - 4 + 12)x + ( - 12) \\ \\ {x}^{3} - 6 {x}^{2} + 5x - 12$