Form a cubic polynomial whose zeros are 2, 4 -2 root 3 and 4+2 root 3.
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Answer:
- sum of zeroes = 2+4-2√3+4+2√3
=10= -b/a
- product of zeroes = 2*4-2√3*4+2√3
=2*(4)sq-(2√3)sq
=2*(16-12)
=2*4
=8=-d/a
- 2*4-2√3+4-2√3*4+2√3+4+2√3*2=c/a
=8-4√3+16-12+8+4√3
=8+8+4=20=c/a
- from above a=1,b=-10,c=20,d=-8
therefore the equation x(cube)-10x(square)+20x-8 is the answer
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